moles of khp to moles of naoh
Now, that's different than asking about pH values in the solution, since the actual [H3O(1+)] level is affected by the various equilibrium reactions the salt ions nominally present may have undergone. a) Calculate the concentration of the NaOH solution 7.50 X 10 -2 moles X 204.22 g KHP/ 1 mole = 15.3 g KHP Number of moles of KHP in 2.00 grams = (m/M) = (2/204.22) mol = 0.00979 mol [c] KHP = n/V = (0.00979/0.1) mol dm -3 Number of moles of KHP in 0.01 dm 3 of solution in conical flask = [c] x V = 0.0979 x 0.01 = 9.79 x 10 -4 mol. diprotic and requires twice the number of moles of NaOH expected for a monoprotic acid. To Submit Your Work: Take photos and submit to Gradescope. Now let's apply the molar ratio logic to obtain the moles Of OH-: .00278 moles of KHP means there's .00278 moles of H+, .00278 moles of H+ means the neutralized solution has.00278 moles of OH-. So, you know that at equivalence point, the reaction will consume #0.0024973# moles of #"KHP"# and #0.0024973# moles of #"NaOH"#, since that's what the #1:1# mole ratio tells you. Nam risus ante, dapibus a molestie consequat, ultrices ac magna.ctum vitae odio. A link to the app was sent to your phone. How many moles of KHP are present in the sample of KHP of student A? Your email address will not be published. Image transcription text11) KHCH404 (KHP) is a monoprotic acid commonly used to standardize aqueous solutions of Also, the % uncertainty of the volume of NaOH was 1.05%, taking the value of 9.50 cm3. Pellentesque dapibus efficitur laoreet. 2 0 obj
moles = mass/MM . What is the exact molarity of the NaOH solution? Lorem ipsum dolor sit amet, consectetur adipiscing elit. Another error was caused by the deviation in the mass of KHP. Since sodium hydroxide reacts 1:1 with the KHP acid this also the number of moles of KHP needed for a complete reaction and neutralization. Fusce dui lectus, congue vel laoreet ac, dictum vitae odio. Nam risus ante, dapibus a molestie conse, onec aliquet. The half equivalence point corresponds to a volume of 13 mL and a pH of 4.6. To achieve this first calculate the number of moles of KHP present in the trial. To get the molar amount of acid used for the experiment, use its molar mass, #0.5100color(red)(cancel(color(black)("g"))) * overbrace("1 mole KHP"/(204.22color(red)(cancel(color(black)("g")))))^(color(purple)("molar mass of KHP")) = "0.0024973 moles KHP"#. Fusce dui lectus, congue vel laoreet ac,gue vel laoreet ac,gue, rem ipsum dolor sit amet, consectetur adipiscing elit. This is an awesome source of information, Thank you ! So I researched what KHP was and found that Steve is correct in that it is Potassium Hydrogen Phthalate. Fusce dui lectus, congue vel laoreet ac, dictum vitae odio. Suppose that a titration is performed and \(20.70 \: \text{mL}\) of \(0.500 \: \text{M} \: \ce{NaOH}\) is required to reach the end point when titrated against \(15.00 \: \text{mL}\) of \(\ce{HCl}\) of unknown concentration. b) Determine the molecular mass of the unknown monoprotic acid %PDF-1.5
answered 11/22/13, Patient and Knowledgable Math and Chemistry Tutor, Stanton D. answered 07/11/19, Experienced Pres. Finally, divide the moles of \(\ce{H_2SO_4}\) by its volume . Lorem ipsum dolor sit amet, consecec facilisis. Most questions answered within 4 hours. Therefore, due to flaws in raw data values taken from systematic errors, there has been a deviation in uncertainty too, indicating the impact of methodical flaws. Show all of your work for each question. stream
Pellentesque dapibus efficitur laoreet. The primary standard acid to be used is potassium hydrogen phthalate (hereafter referred to as KHP). c) Calculate the Ka of the unknown monoprotic acid Show more, 11) KHCH404 (KHP) is a monoprotic acid commonly used to standardize aqueous solutions of It is not hygroscopic. Donec aliquet. 1 0 obj
That's one problem with abbreviations. Nam risus ante, dapibus a molestie consequat, ultr, ultrices ac magna. %
A sample of 354.5 mg of KHP is added to water, which is then neutralized by However, the amount I added on an average was 10.4 cm3, which suggests why the solution became unusually dark pink as supposed to light pink. . The molarity of the NaOH solution is Pellentesque dapibus efficitur laoreet. 0.02965-0= 0 L One experimental flaw which resulted in readings inconsistent with the literature value was due to human error. answered 11/20/13, Andre W. The percent error that has resulted in: 9.03% is by far a significant error that has resulted from a small error in the volume. Conc. your work. Your goal here is to standardize a solution of sodium hydroxide, #"NaOH"#, by using potassium hydrogen phthalate, #"KHP"#. You get .00278 moles of KHP. How do you calculate the number of moles of KHP in NaOH? 1. How does neutralization reaction differ from using a buffer? 17.20 ml of a solution of NaOH(aq). The NaOH may not have reacted with the exact amount of KHP expected. This might have caused some deviations because the volume of sodium hydroxide added was excess. The end-point colour in Experiment 5 is the palest-possible light-pink that won't fade within 30 seconds: Experts are tested by Chegg as specialists in their subject area. Use stoichiometry to determine moles of NaOH reacted. Course Hero is not sponsored or endorsed by any college or university. The balanced chemical equation for the neutralization of KHP with the base NaOH indicates that the stoichiometric molar ratio is 1. Hello..I wanna ask why the theoretical value of concentration of acid-base titration differs from the experimental? However, as NaOH was added further, there came a point when no amount of stirring changed the pink colour. answered 07/11/19, Ph.D. University Professor with 10+ years Tutoring Experience. For Free. Fusce dui lectus, congue vel laoreet ac, dictum vitae odio. Dont forget those significant digits! Lorem ipsum dolor sit amet, consectetur adipiscing elit. a) Calculate the concentration of the NaOH solution Nam lacinia pulvinar tortor nec facilisis. Fusce dui lectus, congue vel laoreet ac, dictum vitae odio. Type of Acid/Base Indicator used Phenolphthalein. 3 0 obj
The volume of \(\ce{H_2SO_4}\) required is smaller than the volume of \(\ce{NaOH}\) because of the two hydrogen ions contributed by each molecule. To add to Andre's notes above: It's irrelevant that the KHP solution (which is chemically ambiguous, is it K2HPO4 or is it KH2PO4? KHP is an acid with one acidic proton. Nam risus ante, dapibus a molestie consequat, ultrices ac magna. Oliver Twist: Characters, Setting, Style, Audience and Diction, On the Sidewalk, Bleeding: Analysis & Theme, Carolyn Meyers White Lilacs: Summary, Conflict, Analysis, President Ronald Reagans John F. Kennedy Speech: Analysis, Refractive Indices of Water and Oil: Lab Explained, Volume of NaOH added [since the colour change will not happen at, Average Volume of NaOH added in 3 trials (0.1 cm. Fusce dui lectus, congue vel laoreet ac, dictum vitae odio. Calculate the concentration of the NaOH solution. To get the molar amount of acid used for the experiment, use its molar mass 0.5100 g molar mass of KHP 1 mole KHP 204.22 g = 0.0024973 moles KHP The higher molarity of the acid compared to the base in this case means that a smaller volume of the acid is required to reach the equivalence point. I started to make the same mistake as you. How can you determine the strength of sulfuric acid? Donec aliquet. Lorem ipsum dolor sit amet, consectetur adipiscing elit. Introduction Sodium hydroxide is hygroscopic and absorbs water from the air when you place it on the balance for massing. Nam risus ante, dapibus a molestie consequat, ultr, at, ultrices ac magna. 0 moles However, there has been a deviation of 0.9 cm3, which is significant, but not high. These errors were avoidable. This will be a strong base - weak ac. Full Beaker= 25. First determine the moles of \(\ce{NaOH}\) in the reaction. Therefore, one mole of KHP reacts with one mole of NaOH: KHC8H404 (aq) + NaOH (aq) NakCxH404 (aq) + H2O (1). Fusce dui l, m ipsum dolor sit amet, consectetur adipiscing, sus ante, dapibus a molestie consequat, ultrices ac magna. 20. molecular equation: KHC8H4O4(aq) + NaOH (aq) KNaC8H4O4(aq) + H2O(l) Do not round off any intermediate results during this multi-step calculation . Lorem ipsum dolor sit amet, consectetur adipiscing elice dui lectus, congue vel laoreet ac, dictum vitae odio. 0. Choose an expert and meet online. { "21.01:_Properties_of_Acids" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.
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